Bangkok, Thailand is the 3rd cheapest city in the world offering five-star luxury for $108.
The research from Luxury Hotel analysed the cost of a one night stay at five-star hotels across the world to reveal the cheapest cities in the world for a night of luxury.
The 10 cheapest cities in the world for five-star hotels
Rank |
City |
Price per night in 5* hotel |
1 |
Kuala Lumpur, Malaysia |
$94 |
2 |
Ho Cho Minh City, Vietnam |
$104 |
3 |
Bangkok, Thailand |
$108 |
4 |
Antalya, Turkey |
$108 |
5 |
Mexico City, Mexico |
$118 |
6 |
Sapporo, Japan |
$118 |
7 |
Hanoi, Vietnam |
$118 |
8 |
Phuket, Thailand |
$120 |
9 |
Chiang Mai, Thailand |
$123 |
10 |
Mecca, Saudi Arabia |
$134 |
Bangkok, Thailand is the 3rd cheapest city in the world for five-star hotels, with a price of $108 per night. 8 of the 10 cheapest places for five-star hotels are in Asia, one in each of Europe and North America.
Further findings:
- The global average of a one night stay in a five-star hotel is $272, in comparison, Europe’s average is $286.
- Mexico City, Mexico, is North America’s cheapest five-star destination costing $118. It was followed by Punta Cana, Dominican Republic ($246) and Las Vegas, USA ($273).
- Doha, Qatar has the highest proportion of five-star hotels, with 51.43% of its hotels being five-star. New York has the highest proportion of five-star hotels in the US, with 14.22%.
Theodore is the Co-Founder and Managing Editor of TravelDailyNews Media Network; his responsibilities include business development and planning for TravelDailyNews long-term opportunities.