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The cheapest cities in the world for 5* hotels have been revealed

Bangkok, Thailand is the 3rd cheapest city in the world offering five-star luxury for $108.

The research from Luxury Hotel analysed the cost of a one night stay at five-star hotels across the world to reveal the cheapest cities in the world for a night of luxury.

The 10 cheapest cities in the world for five-star hotels

Rank

City

Price per night in 5* hotel

1

Kuala Lumpur, Malaysia

$94

2

Ho Cho Minh City, Vietnam

$104

3

Bangkok, Thailand

$108

4

Antalya, Turkey

$108

5

Mexico City, Mexico

$118

6

Sapporo, Japan

$118

7

Hanoi, Vietnam

$118

8

Phuket, Thailand

$120

9

Chiang Mai, Thailand

$123

10

Mecca, Saudi Arabia

$134

Bangkok, Thailand is the 3rd cheapest city in the world for five-star hotels, with a price of $108 per night. 8 of the 10 cheapest places for five-star hotels are in Asia, one in each of Europe and North America. 

Further findings: 

  • The global average of a one night stay in a five-star hotel is $272, in comparison, Europe’s average is $286. 
  • Mexico City, Mexico, is North America’s cheapest five-star destination costing $118. It was followed by Punta Cana, Dominican Republic ($246) and Las Vegas, USA ($273).
  • Doha, Qatar has the highest proportion of five-star hotels, with 51.43% of its hotels being five-star. New York has the highest proportion of five-star hotels in the US, with 14.22%.
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